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We saw earlier that the energy of the electron in a hydrogen atom depends only on the principal quantum number, n. The nucleus of a hydrogen atom has a charge of +1, however, if the electron is bound to a nucleus of arbitrary charge +Z, then the energy of the electron is
This expression is for a single electron orbiting a single nucleus of charge +Z. If I had a mole of atoms like this, then I could multiply this expression by Avogadro's Number to get the total energy for all the atoms:
This equation is so popular that the number 1312 is named the Rydberg Constant and given the symbol RH = 1312 kJ/mole.
Let's look carefully at this equation:
Let's look at the energy levels of the hydrogen atom.
For the hydrogen atom Z=1 so En= - RH/n2
Notice that the energy level spacing decreases as n increases, that the number of orbitals (i.e. l values) increase with n, and all orbitals with the same n have the same energy (degenerate). (H-atom only).
We can look at either absorption or emission spectra.
Using our equation for the energy of the hydrogen levels we can write an equation for the change in energy of an electron that charges orbitals and emits or absorbs a photon.
With this equation we can calculate the frequency of light emitted or absorbed when an electron moves between orbitals of different principal quantum numbers.
Using the equation above we can calculate the wavelengths for various transitions in the H-atom.
|ni → nf||Wavelength|
|3 → 2||λ=657 (red)|
|4 → 2||λ=487 (green)|
|5 → 2||λ=435 (blue)|
|∞ → 2||λ=365 (purple)|
The energy required to promote an electron to n = ∞ is called the ionization energy.
(Because this is the energy required to make an ion).
Chemisty, The Central Science, 10th Ed.
6.33, 6.35, 6.37, 6.39
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